Mathematics: Atotal of $11,000 is invested in two accounts. part was invested at 4% and the rest was invested at 7%. if the investments earn $680 peer year, how much was invested at each rate? i=prt

20.125 milesStep-by-step explanation:Use cross multiplication method....

Atotal of $11,000 is invested in two accounts. part

yasdallasj

12.01.2022

The amount invested at 4% was $3,000 and the amount invested at 7% was $8,000

Step-by-step explanation:

we know that

The simple interest formula is equal to

I=P(rt)

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

$t=1\ year\\ P_1=x\\P_2=11,000-x\\I=\$680\\r_1=4\%=4/100=0.04\\r_2=7\%=7/100=0.07$

substitute in the formula above

I=P_1(r_1t)+P_2(r_2t)

680=0.04x+(11,000-x)0.07

solve for x

680=0.04x+770-0.07x

0.07x-0.04x=770-680

0.03x=90

$x=\$3,000$

$\$11,000-x=\$11,000-\$3,000=\$8,000$

therefore

The amount invested at 4% was $3,000 and the amount invested at 7% was $8,000

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