Nessakona1
03.08.2019 •
Mathematics
Atoy manufacturer inspects boxes of toys before shipment. each box contains 19 toys. the inspection procedure consists of randomly selecting three toys from the box. if one or more of the toys are defective, the box is not shipped. suppose that a given box has two defective toys. what is the probability that it will be shipped?
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Ответ:
The probability that a box with two defective toys will be shipped is 0.29825
Step-by-step explanation:
The first toy picked has a 17 in 19 chance of not being defective
The second toy picked has a 16 in 18 chance of not being defective
The third toy picked has a 15 in 17 chance of not being defective
The probability that the toy is not defective, and will be shipped
P(toy not defective and shipped) = (17/19) *(16/18)*(15/17)
= (16*15)/(19*18)
= 240/342
= 0.70175
The question said, suppose that a given box has two defective toys, what is the probability that it will be shipped?
P( toy defective and not shipped) = 1 - P(toy not defective and shipped)
= 1-0.70175
= 0.29825
The probability that a box with two defective toys will be shipped is 0.29825
Ответ:
Step-by-step explanation:
the answer is
(2x+13)=(3x-3)
x= 16