Mathematics: Atoy manufacturer wants to know how many new toys children can buy each year. he thinks the mean is 6.9 toys per year. assume a previous study found the standard deviation to be 1.3. how large a sample would be required in order to estimate the mean number of toys bought per child at the 98% confidence level with an error at most 0.11 toys?

Atoy manufacturer wants to know how many new

holycow4916

16.03.2022

758

Step-by-step explanation:

Given : Mean : $\mu=6.9 \text{ toys per year]$

Standard deviation : $\sigma = 1.3$

Margin of error : $E=0.11\text{ toys}$

Significance level : $\alpha=1-0.98=0.02$

Critical value : $z_{\alpha/2}=2.33$

Formula for sample size :-

$n=(\dfrac{z_{\alpha/2}\sigma}{E})^2\\\\\Rightarrow\ n=(\dfrac{2.33\times1.3}{0.11})^2=758.251322314\approx758$

Hence, the minimum required sample size = 758

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jasminer257

22.01.2023

The answer is 1/4

Step-by-step explanation:

It's 1/4 because it's the least amount and it has x's above it.

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