Atrapezoid has an area of 30 in. if the lengths of the bases are 4.8 in. and 5.2 in., what is the height.

We know that the formula to solve for the area of a trapezoid is A=(a+b)/2+h. So, the formula to find the height would be 2*[A/(a+b)].
2*[A/(a+b)] Substitute the values for the variables
2*[30/(4.8+5.2)] Solve the parentheses
2*(30/10)
2*3=6
The height must be 6 inches.

3/4 i believe                                               not totally sure