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mayapril813
23.11.2019 •
Mathematics
Atriangular prism and two nets are shown:
a right triangular prism is shown with two nets. the triangular base of the prism has height 5 inches, base 12 inches, and hypotenuse 13 inches. the length of the prism is 14 inches. net a has 3 rectangles having dimensions 5 by 14, 14 by 12, and 14 by 13, and two triangles having legs 5 inches and 12 inches. net b has 3 rectangles having dimensions 5 by 13, 13 by 12, and 13 by 14, and two triangles having legs 5 inches and 12 inches.
which is the correct net of the prism and what is the surface area of the prism?
pick from the three answers below
net a with 420 square inches
net a with 480 square inches
net b with 510 square inches
net b with 534 square inches
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Ответ:
Option B. Net A with 480 square inches.
Step-by-step explanation:
The net for triangular prism consists of
2 identical triangles, here all nets have sides 5", 12", and 13".
3 rectangles, all with a common dimension: the Length or height
H=14 inches of the prism.
Each of the 3 rectangles should have dimensions
H=14 plus one of the following:
each of 5, 12, 13 corresponding to one side of the base (triangle).
So the dimensions of the rectangles are
5 × 14, 12 × 14, 13 × 14
And dimensions of the triangles are
5,12 and 13.
The total surface area is therefore
(5+12+13)×14 + 2×(5×12/2)
(30)(14)+2(60/2)
= 420+2(60/2)
= 420+2(30)
= 420+60
= 480 square inches.
Net A with 480 square inches is the correct net of the prism.
Ответ:
The answer is B Net B with 480 square inches. I took the test and got it right. Have a great dday.
Step-by-step explanation:
Ответ:
52
Step-by-step explanation:
Multiply 0.65 by 80
0.65 is the same as 65%
52 is the answer
Hope this helps :)
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