Atropical species of mite named archegozetes longisetosus is the record holder for the strongest insect in the world. it can lift up to 1.182 x 10^3 times it's own weight. a. if you were as strong as this insect, explain how you could find how many pounds you could lift. b. complete the calculation to find how much you could lift, in pounds, if you were as strong as an archegozetes longisetosus mite. express your answer in both scientific notation and standard notation.

A tropical species of mite named Archegozetes longisetosus can lift up to times it's own weight.

A:

Let the weight of the insect be = x pounds

So, it can lift pounds

B:

Let us assume that you weigh 135 pounds.

So, the weight that you can lift is = pounds.

That will be = pounds

or   pounds

The area of figure is: 2313

Step-by-step explanation:

We need to find area of the figure.

Figure is composed of one square and 4 semicircles.

So, we find area of both square and semicircles.

First we will find area of square.

Length of square = 30

The formula used is:

Putting values and finding area of square

Now, we will find the area of semicircle

Diameter of semicircle = 30

Radius r = d/2 = 30/2 = 15

Now, The formula used is:

Putting values and finding area of semicircle

Now, we have 4 semicircles, all will have same area as their diameter is 30

So,

So, the area of the figure will be:

Area of figure= Area of Square+ Area of 4 semicircles

Area of figure = 900+1413

Area of figure=2313

So, the area of figure is: 2313