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patience233
31.08.2019 •
Mathematics
Atrough is 15 ft long and 4 ft across the top. its ends are isosceles triangles with height 3 ft. water runs into the trough at the rate of 2.5 ft3/min. how fast is the water level rising when it is 0.89 ft deep? give your answer correct to 3 decimal places.
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Ответ:
V = L*w*h
Since L and w are constants, and h does only change as the water rises up, the rate of change of that volume by using the derivative is
dV/dt = L*w*dh/dt
Given dV/dt = 2.5 ft3/min, then
2.5 = 4*15*dh/dt
dh/dt = 1/24 ≈ 0.042 ft/min
Ответ:
12.5 hours
Step-by-step explanation:
budget: 200
fix cost: 50
hourly rate: 12
hours: ?
First we deduct the fix 50 dollars cost from the total budget.
Then we divide the remaining amount with the hourly rate
( 200 - 50 ) / 12 = ?
? = 12.5 hours