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alejandra216
27.11.2019 •
Mathematics
Atumor is injected with 0.4 grams of iodine-125, which has a decay rate of 1.15% per day. to the nearest day, how long will it take for half of the iodine-125 to decay?
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Ответ:
The Time period required for decay of Iodine-125 to half of its value is 60 days .
Step-by-step explanation:
Given as :
The initial quantity of iodine-125 = 0.4 gram
The rate of decay = 1.15 %
Let The time period for decay = x day
The finial quantity after decay = half of initial quantity
I.e The finial quantity after decay = 0.2 gram
Now ,
The final quantity after decay = initial quantity ×![(1-\dfrac{\textrm rate}{100})^{\textrm Time}](/tpl/images/0393/8059/4fcf3.png)
Or, 0.2 gm = 0.4 gm ×![(1-\dfrac{\textrm 1.15}{100})^{\textrm x}](/tpl/images/0393/8059/43768.png)
or,
= ![(0.9885)^{x}](/tpl/images/0393/8059/028ac.png)
Or, 0.5 =![(0.9885)^{x}](/tpl/images/0393/8059/028ac.png)
Or,
= 0.9885
Taking log both side
log (
) = Log 0.9885
or,
× log 0.5 = - 0.0050233
or,
× ( - 0.301029 ) = - 0.0050233
or, x =![\dfrac{0.301029}{0.0050233}](/tpl/images/0393/8059/7c160.png)
∴ x = 59.92 ≈ 60 days
Hence The Time period required for decay of Iodine-125 to half of its value is 60 days . Answer
Ответ:
this is tating the plant