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11.07.2019 •
Mathematics
Aveterinarian wishes to use 132 feet of chain link fencing into two smaller rectangels having the same lengths and same widths. of the total enclosed anrea is 576 square feet, find the dimensions of the enclosed region
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Ответ:
to better understand the problem see the attached figure
Let
x-------> the length of one rectangle of the enclosed region
y------> the width of one rectangle of the enclosed region
we know that
the dimensions of the enclosed region are
Length=2x
Width=y
the perimeter of one rectangle is equal to
P=2x+2y
in this problem
the perimeter of the enclosed region is equal to
132=[4x+3y]
132=4x+3y------> equation 1
the area of one rectangle is equal to
A=x*y
in this problem
576=[2x*y] ------> equation 2
Solve the system
132=4x+3y------> equation 1
576=[2x*y] ------> equation 2
using a graph tool-------> to solve the system equation
see the attached figure
the solution is
x=24 ft
y=12 ft
therefore
the answer is
the dimensions of the enclosed region are 48 ft * 12 ft
Ответ: