marbuscis99
01.08.2019 •
Mathematics
Aweighted die, numbered one through six, has a probability of 1/4 of rolling a six. if this die is rolled three times, and each roll is independent, what is the probability of rolling at least two sixes?
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Ответ:
Step-by-step explanation:
Three events A, B and C are said to be independent if occurrence of one outcome does not affect the other .
In such case P ( A and B and C ) = P(A) × P(B) × P (C)
Given : A weighted die, numbered one through six, has a probability of 1/4 of rolling a six .
As the die is rolled three times, possible outcomes are
Let E denotes the event: 6 occurs
Let F denotes the event that 6 does not occur .
Given: P(E) =
So, P(F) =
Therefore, probability of rolling at least two sixes =
Ответ:
what are the answers
Step-by-step explanation: