Awell-known author has postulated that 10% of all medicare claims are fraudulent. suppose we were to review 10 medicare claims. the binomial table for this event space is below: b~(10,0.1) p(x=k) p(x≤k) k π k π 0 0.3487 0 0.3487 1 0.3874 1 0.7361 2 0.1937 2 0.9298 3 0.0574 3 0.9872 4 0.0112 4 0.9984 5 0.0015 5 0. 6 0.0001 6 1.000 7 0. 7 1.000 8 0. 8 1.000 9 0. 9 1.000 10 0. 10 1.000 given the above information: a. how many claims would we expect to be fraudulent? b. what is the standard deviation? c. what is the probability that exactly 3 medicare claims are fraudulent? d. what is the probability that more than 3 claims are fraudulent? e. what is the probability that 3 to 5 claims are fraudulent?

a) 1; b) 0.95; c) 0.0574; d) 0.0128; e) 0.0127

Step-by-step explanation:

For part a,

To find the number we would expect (the mean), we multiply the sample size by the probability of success:

10(0.1) = 1

For part b,

To find the standard deviation, we use

Our n is 10, p is 0.1; this makes q = 1-0.1 = 0.9:

For part c,

We use the binomial table, looking up P(X = 3):  0.0574

For part d,

We start out finding P(X ≤ 3):  0.9872.  However, we want P(X > 3), so we subtract from 1:

1-0.9872 = 0.0128

For part d,

We find P(X ≤ 3) and P(X ≤ 5) then subtract:

P(X ≤ 3) = 0.9872; P(X ≤ 5) = 0.9999

0.9999-0.9872 = 0.0127

h = -25.2

Step-by-step explanation:

To solve the equation, you want to isolate the h variable. To do this, move 12.6 to the other side of the equation. Since you were adding on the left side, use the inverse operation, subtracting, on the right. Simplify the result to get the answer.

h + 12.6 = -12.6

h = -12.6 - 12.6

h = -25.2