Awire carries 8 a of current directed to the left. what is the magnitude of the initial force on a +6 mc charged particle that is moving at a speed of 2000 m/s to the left at a distance 6.0 mm from the wire?

a. 2.7 x 10-4 n
b. 3.2 x 10-3 n
c. 4.32 n
d. 0 n

Multiply the first equation by 4 and the second equation by -3:

-12x + 16y = 4

12x - 15y = -6

‣ Add the equations:

‣ Solve for y:

y = -2

‣ Substituting y = -2 into the first equation, we get:

-12x + 16 ⋅ (-2) = 4

‣ Solve for x:

x = -3

‣ Solution:

x = -3, y = -2)

DUDE SORRY My first answer wrong, I'm a bit tired but here you go