Mathematics: B(1)= -12 b(n)=b(n−1)⋅4Find the 3rd term of the sequence. Show me the solutions and calculations.

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B(1)= -12 b(n)=b(n−1)⋅4Find the 3rd term of the

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18.04.2021

Given:

b(1)=-12

$b(n)=b(n-1)\cdot 4$

To find:

The third term of the sequence.

Solution:

We have,

$b(n)=b(n-1)\cdot 4$

For n=2, we get

$b(2)=b(2-1)\cdot 4$

$b(2)=b(1)\cdot 4$

$b(2)=-12\cdot 4$ $[\because b(1)=-12]$

b(2)=-48

For n=3, we get

$b(3)=b(3-1)\cdot 4$

$b(3)=b(2)\cdot 4$

$b(3)=-48\cdot 4$ $[\because b(2)=-48]$

b(3)=-192

Therefore, the 3rd term of the sequence is -192.

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