Ben has $3.40 consisting of quarters and dimes. how many coins of each kind does he have if he has 22 coins?

show a system of equation to represent the word problem.

There are 8 quarters and 14 dimes.

Step-by-step explanation:

Let there are x quarters.

and y dimes.

Also as we know,

1 quarter= 0.25 dollar

Hence, x quarter= $ 0.25x

and 1 dime= $ 0.10

Hence,  y dimes= $ 0.10y

Ben has $3.40 consisting of quarters and dimes.

This means that:

                 0.25x+0.10y=3.40

Also, in non-decimal form it could be written as:

                  25x+10y=340

He has 22 coins

This means that:

                       x+y=22

Now on solving it graphically we see what is the point of intersection of the two lines or system of linear equations.

We get the point of intersection as: (8,14)

i.e. x=8 and y=14

Hence, there are 8 quarters.

and 14 dimes.

We have the expression for a number of calories versus person's weight. The expression is y = 9.56x + 495.35.

When Jill consumes 1850 calories, her weight is:
1850 = 9.56 x +495.35
x = 141.7 pounds

When Jaxon is 120 pounds, the calories that he consumed is:
y = 9.56 (120) + 495.35
y =1,635.35 calories

Therefore, Jill is heavier and with greater consumption of calories.