Benjamin& associates, a real estate developer, recently builit 209 condominiums in mccall, idaho. the condos were either two-bedroom units or three-bedroom units if the total number of rooms in the entire complex is 530, how many two-bedroom units are there? how many three-bedroom units are there? there are a. two-bedroom units and b. three-bedroom units

2 bed room condos are 97 and 3 bed room condos are 112.

Step-by-step explanation:

Consider the provided information.

Benjamin& Associates, a real estate developer, recently builit 209 condominiums in McCall, Idaho.

Let number of 2 bed room units = x and 3 bed room units = y.

The total number of rooms in the entire complex is 530,

Substitute the value of y in above equation.

Now find the value of y as shown

Hence, 2 bed room condos are 97 and 3 bed room condos are 112.

Smallest number = 3500

Step-by-step explanation:

Rounding of numbers involve replacing numbers with simpler numbers. In order to round a number to the nearest thousand, the last 3 digits of the number should be considered. If the last 3 digits are less than 500, the number is rounded down(the thousand figure is unaffected), but if the last 3 digits are greater or equal to 500, the number is rounded up.

In this case, Yuri is thinking of a 4-digit whole number and he rounds his number to the nearest thousand. Since his answer is 4000, the smallest number yuri could be thinking of would be 3500 and the highest number he could be thinking of is 4499.

Thus, the smallest number Yuri could be thinking of is 3500