Brenda bought three times more black fabric than

Ответ:

anyaimartinez1901

15.12.2022

Mathematics

$0.1546\leq \widehat{p}\leq 0.3513$

Step-by-step explanation:

The firm tests 75 parts, and finds that 0.25 of them are notusable

n = 75

x = 0.25 \times 75 = 18.75≈19

$\widehat{p}=\frac{x}{n}$

$\widehat{p}=\frac{19}{75}$

$\widehat{p}=0.253$

Confidence level = 95%

So, Z_\alpha at 95% = 1.96

Formula of confidence interval of one sample proportion:

$=\widehat{p}-Z_\alpha \sqrt{\frac{\widehat{p}(1-\widehat{p}}{n}}\leq \widehat{p}\leq \widehat{p}+Z_\alpha \sqrt{\frac{\widehat{p}(1-\widehat{p}}{n}}$

$=0.253-(1.96)\sqrt{\frac{0.253(1-0.253)}{75}}\leq \widehat{p}\leq0.253+(1.96)\sqrt{\frac{0.253(1-0.253}{75}}$

Confidence interval $=0.1546\leq \widehat{p}\leq 0.3513$

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Brenda bought three times
more black fabric than red
fabric. She bought 72 inches
of red fabric. If fabric costs
$725 per yard, how much did
Brenda spend on fabric?

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Brenda bought three times more black fabric than red fabric. She bought 72 inches of red fabric. If fabric costs $725 per yard, how much did Brenda spend on fabric?

Ответ:

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Brenda bought three times
more black fabric than red
fabric. She bought 72 inches
of red fabric. If fabric costs
$725 per yard, how much did
Brenda spend on fabric?