Brian bought x apples and some oranges brian bought three more oranges and apples find the total number of fruit brian bought in terms of x. If Brian could have bought exactly 12 pears with the amount of money that was spent on apples and oranges, find the cost per year, in cents, in terms of x

0.76%

Step-by-step explanation:

This exercise is solved through combinations.

The first is the number of combinations of students that would go in that course, that is, 5 out of 40.

Formula: nCx = n! / X! * (N-x)!

 40C5 = 40! / [5! * (40 - 5)!] = 658008

Also the number of combinations of the other members of the audience that occupy the other 4 places (9 in total - 5 of the group), that is 4 of 90 (130 total - 40 of the group658008po).

90C4 = 90! / [4! * (90 - 4)!] = 2555190

The total of possible combinations 9 contestants with 5 students in them, would be:

40C5 * 90C4

Now, the total number of possible 9 contestants from the audience would be 9 in 130:

130C9 = 130! / [9! * (130 - 9)! = 2.2016 * 10 ^ 13

The probability would be equal to:

40C5 * 90C4 / 130C9 = 658008 * 2555190 / (2.2016 * 10 ^ 13) = 0.076

In other words, the probability is 0.76%