AshlynPlayz45
07.10.2020 •
Mathematics
Brian has 64 flowers for a big party decoration. In addition, he is planning to buy some flower arrangements that have 18 flowers each.
All of the arrangements cost the same. Brian is not sure yet about the number of flower arrangements, he wants to buy, but he has enough money to buy up to 5 of them. Write a function to describe how many flowers Brian can buy.
Let x represent the number of flower arrangements Brian buys.
Find a reasonable domain and range for the function.
f(x) = 18x + 64 Domain: {0, 1, 2, 3, 4}; Range: {64, 82, 100, 118, 136}
f(x) = 18x + 64 Domain: {0, 1, 2, 3, 4, 5}; Range: {64, 82, 100, 118, 136, 154}
f(x) = 64x + 18 Domain: {1, 2, 3, 4}; Range: {82, 100, 118, 136, 154}
f(x) = 64x + 18 Domain: {5}; Range: {154}
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Ответ:
The answer is 18x+64 ={the five terms it gives you} <(they might be different for everyone)
Step-by-step explanation:
I had the same question on my quiz and I used process of elimination to get the answer. According to my quiz, I'm assuming that you've had the same four answer choices that I had.
First off, the variable must be on 18, since it says 18 flowers each, which will eliminate two answer choices, another piece of evidence is that X is supposed to represent the numbers of flower arrangements.
Now we are left with two different answer choices, one of which is missing a term. This is a problem since it says that he has enough to have up to five of them. Since one of the answer choices has only four terms, it is safe to say it is incorrect.
Conclusion
This leads the answer to be 18x+64={five terms, not four}
I hope this helps, good luck on the rest of your assignment/quiz! :D
Ответ:
Step-by-step explanation:
step 1. so you want to graph 2 linear equations?
step 2. y = (-1/3)x + 6. put a dot on the y intercept (0, 6).
step 3. draw the line through (0, 6) with a slope of -1/3 (down 1 and to the right 3).
step 4. y = 3x + 6. put a dot on the y intercept (0, 6).
step 5. draw the line through (0, 6) with a slope of 3/1 (up 3 and to the right 1).