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brittanysanders
24.09.2019 •
Mathematics
Bruce had an ekg to measure his heartbeat rate. after conversion, the function produced could be modeled by a cosine function, and the wave produced a maximum of 4, minimum of −2, and period of pi over 2. which of the following functions could represent bruce's ekg read-out?
f(x) = 4 cos pi over 2x − 2
f(x) = 3 cos 4x + 1
f(x) = 3 cos pi over 2x + 1
f(x) = 4 cos 4x − 2
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Ответ:
Option B.
Step-by-step explanation:
Bruce had an EKG to measure his heartbeat rate. After conversion, the function produced was modeled by a cosine function.
Now we will form this function.
Function will be in the form of f(x) = a cos(Bx) + d
Amplitude![a=\frac{Maximum-minimum}{2}](/tpl/images/0256/9218/0ef85.png)
Period = π/2
And![Period=\frac{2\pi }{B}](/tpl/images/0256/9218/d9299.png)
⇒![\frac{\pi }{2}=\frac{2\pi }{B}](/tpl/images/0256/9218/9f910.png)
⇒ B = 4
Since minimum is (-2) and maximum is (4), means cosine graph was shifted upwards.
Mid line of the graph is
which shows graph is shifted by one unit above the x-axis.
Now the function we get is f(x) = 3 cos4x + 1
Therefore option B is the answer.
Ответ:
i dont know
Step-by-step explanation:
im sorry