Bryce has 10 bals in a bag, each having a distinct color. He randomly picks a ball from the bag 4 times, with replacement. The expected number of distinct colors among the 4 balls Bryce picks can be expressed as a simplified fraction p q . Find p q.

p = 1 ; q = 10,000

Step-by-step explanation:

Number of distinct colored balls = 10

Number of balls picked with replacement = 4

Probability = (number of required outcome / number of total possible outcomes)

Distinct picks :

P(1st) = 1 /10

P(2nd) = 1/10

P(3rd) = 1/10

P(4th) = 1/10

Expected Numbe of distinct color:

P(1st) * P(2nd) * P(3rd) * P(4th)

1/10 * 1/10 * 1/10 * 1/10

= 1/10000

p/q = 1/ 10000

p = 1 ; q = 10,000