Building A is 226 meters taller than building B. If the height of building A is subtracted from twice the height of building B, the result is 276 meters. How tall is each skyscraper?

Building A is 338 meters taller than building B. If the height of building A is subtracted from twice the height of building​ B, the result is 131 meters. How tall is each​ skyscraper?

Let a = the height of building A and b = the height of building B.

You get a = b + 338

if you subtract the height of building A from twice the height of building B, then you get:

2b - a = 131.

You have 2 equations to be solved simultaneously.

They are:

a = b + 338

2b - a = 131

in the second equation, replace a with its equivalent value from the first equation to get:

2b - (b + 338) = 131

simplify to get 2b - b - 338 = 131

combine like terms to get b - 338 = 131

Add 338 to both sides of the equation to get b = 469.

That's the height of building B.

Since building A is 338 meters higher than that, then building A must be 807 meters high.

You get building A is 807 meters high and building B is 469 meters high.

Building A is 807 - 469 = 338 meters higher than building B.

If you subtract the height of building A from twice the height of building B, you get 2 * 469 - 807 = 938 - 807 = 131 meters difference.

Solution to the first question looks good.

Building A is 807 meters high and building B is 469 meters high.

Second question:

During his tennis career in singles​ play, John won 33 fewer tournament A titles than tournament B titles and 22 more tournament C titles than tournament B titles. If he won 20 of these titles​ total, how many times did he win each​ one?

Let a = number of tournament A titles won.

Let b = number of tournament B titles won.

Let c = number of tournament C titles won.

Since total number tournament titles won is 20, you get:

a + b + c = 20

since he won 33 fewer tournament A titles than tournament B titles, you get:

a = b - 33

since he won 22 more tournament C titles than tournament B titles, you get:

c = b + 22.

Replacing a and c with their equivalent values from the first 2 equations, you get the third equation becoming:

b - 33 + b + b + 22 = 20

combine like terms to get 3b - 11 = 20

add 11 to both sides to get 3b = 31

Divide both sides by 3 to get b = 10 and 1/3.

Since a = b - 33, this makes a = - (22 and 2/3).

Since c = b + 22, this makes c = 32 and 1/3.

a + b + c = 20, but

An is negative which can't be, indicating there is something wrong with the equation.

I suspect that the total number of tournaments won have to be a number greater than or equal to 33 in order for a to be greater than or equal to 0.

i don't believe there is a valid solution to this problem the way it is presented.

first of all, the value of b was not an integer.

second of all, the value of a is negative.

these are two indications that there is something wrong with the equation the way it is presented.

the mean is 69.75

the median is 89.5

the measure of center that helped the most is the median

i hoped this helped!