(c) for what value of the domain(-3,-1,0,2,5) does f(x)= g(x) (-3,-1,0,2,5) ?

Info from question

so we have
f(x)=3x-4 and
g(x)=x(2)-2
the x(2) should mean 2 times x or 2x, but if it means x^2 then
g(x)=x^2-2
solution set is represented by S={solutions}
so to see what values make them equal, we set them equal to each other

if x(2)=2x then go to
if x(2)=x^2 then go to


3x-4=2x-2
subtract 2x from boths ides
x-4=-2
add 4 to both sides
x=2
therefor the number that would satisfy the thingumy is the value of  2 so
S={2}


3x-4=x^2-2
subtract (3x-4) from both sides
0=x^2-3x+2
factor
(x-2)(x-1)=0
set each to zero
x-2=0
x=2

x-1=0
x=1

so the answer is x=1 or 2 so
S={1,2}

so the answer is
if x(2)=2x then S={2}
if x(2)=x^2 then S={1,2}

I think you should first subtract 84 by 6 then 78-6 and continue that.