Mathematics: C is the midpoint of segment AB. Find the value of m+k. A(-3,m) B (4, -1) C (k, 2)

Step-by-step explanation:2(2a + 3b)...

C is the midpoint of segment AB. Find the value of

log3225

01.02.2022

The value of m + k = $5+\frac{1}{2}$ = $\frac{11}{2}$ .

Step-by-step explanation:

We are given that C is the midpoint of segment AB where A(-3,m) , B (4, -1) , and C (k, 2).

As we know that the mid-point formula states that;

Mid-point = $\frac{a+b}{2}$

This means that;

Mid-point of AB = $\frac{A+B}{2}$

C(k, 2) = $(\frac{-3+4}{2}, \frac{m+(-1)}{2} )$

C(k, 2) = $(\frac{1}{2}, \frac{m-1}{2} )$

This means that;

$k = \frac{1}{2}$ and $2=\frac{m-1}{2}$

$k = \frac{1}{2}$ and m-1=4

$k = \frac{1}{2}$ and m = 4+1 = 5

So, the value of m + k = $5+\frac{1}{2}$ = $\frac{11}{2}$ .

0,0(0 оценок)