Calculate the area of the given quadrilaterals.​

dissect the trapezium into a square and triangle. since the triangle is a right angled one the base is 17-7=10cm

the height is found using Pythagorean theorem to be 24cm i.e 26²=x²+10²,x=√(676-100),x=√576,x=24cn

area of trapezium is (1/2)(a+b)h

a is the shorter side and b the longer side

(1/2)*(7+17)24

=288cm²

Answer

I believe it would be a cylinder

Step-by-step explanation: