Arealbot
29.10.2019 •
Mathematics
Calculate the power in kilowats required to lift a 500 kg mass 12 meters in one second
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Ответ:
(a-b) *(a-b) *(a-b)
=(a*a*a) -3*(a*a*b)+3*(a*b*b)-(b*b*b)
34000*(1-7%)*(1-7%)*(1-7%)
=34000*(1-0.07)*(1-0.07)*(1-0.07)
=34000*[(1*1*1)-3*(1*1*0.07)+3*(1*0.07*0.07)-(0.07*0.07*0.07)]
=34000*(1-0.21+0.0147-0.000343)
=34000*(0.804357)
=34*1000*(804.357/1000)
=34*804.357
=27348.138
=27348