Campbells soup company want to create a new sized cam for a new line of soups.If the can holds a volume of 3416.32 cm and the height of the can is 17cm what is the area of the base of the can

Step-by-step explanation:

Volume of the can is expressed as Length *Breadth* Height.

If the area of the can base is Length * Breadth

Volume of the can = area of the base of the can * Height

Given parameters

Volume of the can V = 3416.32cm³

Height of the can h = 17cm

Required

Area of the base of the can

Substituting the given parameters into the formula we have;

V = Ah

A = V//h

A = 3416.32/17

A = 200.96cm²

Hence, the area of the base of the can is 200.96cm²

11.62468045 or 11.6 to 1 decimal place

Step-by-step explanation:

→ We need to utilise trigonometry. The first step would be to list out the formula triangles

Tan = Opposite ÷ Adjacent

Sin =  Opposite ÷ Hypotenuse

Cos = Adjacent ÷ Hypotenuse

→ Now we need to know which triangle to use, we do that by identifying the side or length we are not given in the triangle and then finding a formula without the name of the given side. First let's identify all the sides.

Opposite = AC = 16

Adjacent = BC = We need to find this out

Hypotenuse = AB = No given value

→ Now we look for a formula with hypotenuse

Tan = Opposite ÷ Adjacent

→ The (Tan = Opposite ÷ Adjacent) is the formula we are going to be using. Since we want to find out the adjacent, we have to rearrange to get adjacent as the subject

Adjacent = Opposite ÷ Tan

→ Now we identify the Opposite and the Tan

Opposite = 16

Tan = 54°

Side note ⇒ Sin, cos and tan will always be the angles

→ Substitute in the values in the formula

Adjacent = Opposite ÷ Tan ⇔ Adjacent = 16 ÷ Tan (54) ⇔ Adjacent = 11.6

→ The adjacent is 11.6 to 1 decimal place