Can anyone help me with this question?

x² can be written as (3.8 * 10⁵)² = 3.8² * 10⁵ * ² = 14.44 * 10¹⁰.

x² / y = 14.44 * 10¹⁰ / 5.9 * 10⁴ ≈ 2.45 * 10⁶

Diagonals of regular pentagon trisect all the interior anglesSo, angle ABO will be 1/3 times interior angle ABCso, angle ABO = 36 similarly angle BAO = 36
so angle AOB will be 180 -36-36(because angle in a triangle sum upto 180)
and since EOC is vertical to AOBEOC = AOB