![uehlingt39](/avatars/6118.jpg)
uehlingt39
19.10.2019 •
Mathematics
Can anyone me solve
5 + x^2= 2x^2+ 13
using inverse operations. and provide the steps : )
oh, and remember that you cannot take the square root of a negative number : )
Solved
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Ответ:
Step-by-step explanation:
Here,the given expression is :![5 + x^{2} = 2x^{2} + 13](/tpl/images/0334/8850/8fa10.png)
Now simplifying the expression, we get
⇒![x^{2} - 2x^{2} = 13 - 5](/tpl/images/0334/8850/64592.png)
or,![-x^{2} = 8](/tpl/images/0334/8850/e6796.png)
⇒![x^{2} = -8 \\ or, x^{2} + 8 = 0](/tpl/images/0334/8850/bc326.png)
Now, Since here the roots are NOT REAL but imaginary.
So, try and solve this by![x = \frac{b \pm \sqrt{b^{2} - 4ac } }{2a}](/tpl/images/0334/8850/a1215.png)
here, a = 1, b = 0 and c = 8
So, solving this, we get![x = \frac{\pm \sqrt{-32} }{2} = \frac{\pm 4\sqrt{2} }{2}](/tpl/images/0334/8850/804cb.png)
⇒![x = +2\sqrt{2}i , {\textrm{ or}} x= -2\sqrt{2}i](/tpl/images/0334/8850/34f17.png)
Ответ:
5 horses with a combined weight of 6,240 pounds
horse trailer has a limit of 8,000 pounds of horse and tacks.
Find the weight of tack, t, for each horse that Cari can allow.
5t + 6,240 < 8,000
5t + 6,240 < 8,000
- 6,240 -6,240
5t < 1,760
÷5 ÷5
t < 352
Each horse can carry a tack that weighs no more than 352 pounds.
Any tack that weighs beyond 352 pounds is will exceed the maximum carrying capacity of the horse trailer.