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weisenbergertay5779
21.06.2019 •
Mathematics
Can anyone me with 32,33,36,37,and 40.
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Ответ:
y^2(y-5)=0
y=0,5
33. 18s^3=50s
18s^2=50
s=+\-sqrt(25/9)=5/3,-5/3
36. 4w^4+40w^2-44=0
4(w^4+10w^2-11)=0
(w^2+11)(w^2-1)=0
w=0,1,+\-sqrt(11)
37. 4z^5=84z^3
4z^2=84
z=+\-sqrt(21)
40. 48p^5=27p^3
48p^2=27
p=+\-sqrt(27/48)=+\-sqrt(9/16)=3/4,-3/4
Any question please feel free to ask. Thanks
Ответ:
y=-x+1
Step-by-step explanation: