Can anyone me with both problems ?

1.y=2x+7

2.y=1/2x+2

Step-by-step explanation:

Graph 1-

The slope-intercept form is y=mx+b

b= y-intercept which in graph 1 is 7

so y=mx+7

in order to find m you use the y2-y1/x2-x1 equation.

This means find two coordinates on the graph such as (0,7) and (-1,5).

Now find y2:5

y1:7

x2:-1

x1:0

y2-y1= 5-7=-2

x2-x1= -1

That gives you -2/-1 which you then simplify to = 2

So the graph would be y=2x+7

Graph 2:

You will do the same steps: Find where the line passes through y on a graph, which will be y=2.

b=2

y=mx+2

then find two coordinates, (0,2)(2,3)

y2=3

y1=2

x2=2

x1=0

y2-y1=3-2=1

x2-x1=2-0=2

The slope of the graph which is m= 1/2

y=1/2x+2

Because it would have to be 2x plus 4x to do any thing. 
think of the 2x and 4 as 2 difrent thing only a number with a X like 2x can be added to a number with a x at the end like 4x if both number dont look like this it can not be added 2x+4x