Can anyone solve this question for me? Tommorrow is my test I really need to get goingI need some help?

m = 2, c = -8.

Step-by-step explanation:

The general form of a straight line equation is

y = mx + c    where m = the slope and c is the y-intercept.

We are given the line

y = 2x + 4

Comparing this with the general form we see that the slope of this line  = 2 and the y-intercept C is 4.

Now the given line y = mx + c is parallel to y = 2x + 4 which means that their slopes are the same so we conclude that m = 2.

Now we need to find the value of c which is the y intercept of y = mx + c.

Consider the points A and B:

A is the point where the line y = 2x + 4 intersects the x axis so y = 0 at this point , So substituting in the equation:

0 = 2x + 4

-4 = 2x

x = -2.

So the point A is (-2, 0)

B  is the point where y = 2x + c cuts the x axis so here y = 0:

0 = 2x + c

2x = -c

x = -c/2.

Now we are given that the 2 intercepts are 6 units apart, so:

-c/2 - (-2) = 6

-c/2 + 2 = 6

-c/2 = 4

-c = 8

c = -8.

m^2-2mn+n^2

Step-by-step explanation:

(m-n)^2=m^2-2mn+n^2

(A-B)^2=A^2 - 2AB+B^2