Can i please have some help

Just give her/he the answer she’s/he’s on a time crunch

C is the correct answer

Sub y+2 for x into second equaton

(y+2)^2+y^2+(y+2)y=49
y^2+4y+4+y^2+y^2+2y=49
3y^2+6y+4=49
minus 49 both sides
3y^2+6y-45=0
factor
3(y^2+2y-15)=0
3(y-3)(y+5)=0
set to zero
y-3=0
y=3
y+5=0
y=-5

y=3 and -5

sub back

x=y+2
x=3+2
x=5

x=y+2
x=-5+2
x=-3

the points are
(-3,-5) and (5,3)