wytchnia
20.11.2019 •
Mathematics
Can polynomials have odd roots (like f(x)= cube root of i’ll give branliest!
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Ответ:
I think you're asking if it's possible to have a cube root, fifth root, 7th root, etc of a number as a solution to f(x). The answer is yes it's possible.
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Example:
f(x) = x^3 - 29
This function has one real-number root of (cube root of 29) and the other two roots are complex or imaginary roots.
Ответ:
Yes.
Step-by-step explanation:
A simple example is x^3 - 27 = 0 where one root is x = ∛27
Ответ:
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