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Jasten
27.01.2020 •
Mathematics
Can someone answer these for me? ill give brainliest, i really need to finish : (
(substitution method)
1) -8x+2y=-4
y=-3x-2
2) 12x-3y=4
y=4x
3) 3x+2y=11
x+2y=9
4) -3+2y=5
-4x+y=10
Solved
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Ответ:
Step-by-step explanation:
-8x + 2y = -4 12x - 3y = 4
y = -3x - 2 y = 4x
sub sub
-8x + 2(-3x - 2) = -4 12x - 3(4x) = 4
-8x - 6x - 4 = -4 12x - 12x = 4
-14x = -4 + 4 0 = 4
-14x = 0 NO SOLUTION
x = 0
y = -3x - 2 -3 + 2y = 5
y = -3(0) - 2 -4x + y = 10...y = 4x + 10
y = -2 sub
solution is : (0,-2) -3 + 2(4x + 10) = 5
-3 + 8x + 20 = 5
3x + 2y = 11 8x + 17 = 5
x + 2y = 9...x = 9 - 2y 8x = 5 - 17
sub 8x = - 12
3(9 - 2y) + 2y = 11 x = -12/8
27 - 6y + 2y = 11 x = -3/2
-4y = 11 - 27
-4y = -16 y = 4x + 10
y = -16/-4 y = 4(-3/2) + 10
y = 4 y = -12/2 + 10
y = -6 + 10
x = 9 - 2y y = 4
x - 9 - 2(4) solution (-3/2,4)
x = 9 - 8
x = 1
solution : (1,4)
Ответ:
=![\frac{7x (x + 1)}{(x + 3)(x - 3)}](/tex.php?f= \frac{7x (x + 1)}{(x + 3)(x - 3)} )
=![\frac{7x^2 + 7x}{x^2 - 9}](/tex.php?f= \frac{7x^2 + 7x}{x^2 - 9} )