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ARandomPersonOnline
05.01.2021 •
Mathematics
Can someone answer these two questions I submitted a photo of them it’s worth 50 points
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Ответ:
Step-by-step explanation:
1). Let the equation of the line is,
y = mx + b
Here, m = slope of the line
b = y-intercept
Slope of a line passing through two points,
m =![\frac{y_2-y_1}{x_2-x_1}](/tpl/images/1013/8291/f6758.png)
We take two points from the table given (-3, -19) and (0, -1)
m =![\frac{-19+1}{-3-0}](/tpl/images/1013/8291/553b0.png)
m = 6
y - intercept 'b' = -1 [For x = 0]
Therefore, equation of the line will be,
y = 6x - 1
2). Equation of a line passing through a point (x', y') is,
y - y' = m(x - x')
Slope of the line passing through two points
and
is,
m =![\frac{y_2-y_1}{x_2-x_1}](/tpl/images/1013/8291/f6758.png)
We take two points from the given table as (2, 12) and (3, 18).
Slope of the line passing through these points will be
m =
= 6
Equation of the line passing through (2, 12) will be,
y - 12 = 6(x - 2)
y = 6x - 12 + 12
y = 6x
By using a graphing tool we can graph these lines representing the tables.
Ответ:
Angle A = 55.15 degrees
Step-by-step explanation:
cos^-1(4/7)=Angle A
Therefore, Angle A = 55.15 degrees