Can someone explain how to solve these two math equations?
2x^2-3x-35=0
56z^2+2=22z

#1.

Question:  2x^2 − 3x − 35 = 0

Step 1: Factor left side of equation):    (2x + 7) (x − 5) = 0
Step 2: Set factors equal to 0.):  2x + 7 = 0 or x − 5 = 0

ANSWER: x = −7/2 or x = 5

#2.

Question: 56z^2 + 2 = 22z

Step 1: Subtract 22z from both sides.):

56z^2 + 2 −22z = 22z − 22z
56z^2 − 22z + 2 = 0
Step 2: Factor left side of equation.):


2(7z − 1)(4z − 1) = 0

Step 3: Set factors equal to 0.):


7z − 1 = 0 or 4z − 1 = 0

ANSWER:    z = 1/7 or z = 1/4

191

Step-by-step explanation:

304 divided by 2 equals 152-3=149 340-149=191