Mathematics: Can someone help me with 3???

Step-by-step explanation:we know that The formula to solve a quadratic equation of the form is equal to in this problem we have so substitute in the formula therefore...

Can someone help me with 3??? - id39942216, 12539463

Ответ:

5001Je

18.10.2022

Mathematics

$x^{2} +10x+16=(x+2)(x+8)$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2} +10x+16$

$a=1\\b=10\\c=16$

substitute in the formula

$x=\frac{-10(+/-)\sqrt{10^{2}-4(1)(16)}} {2(1)}$

$x=\frac{-10(+/-)\sqrt{36}} {2}$

$x=\frac{-10(+/-)6} {2}$

$x1=\frac{-10(+)6} {2}=-2$

$x2=\frac{-10(-)6} {2}=-8$

therefore

$x^{2} +10x+16=(x+2)(x+8)$

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Can someone help me with 3???

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