Mathematics: Can someone help me with this math problem?

Can someone help me with this math problem? - id5542729, baby0905rodriguez

kcwolford03

21.01.2022

The area of ΔIDK is 32.69 square units.

Solution:

Given data:

ID = 7 and Hypotenuse, KI = 11.67.

Let us first find KD:

Using Pythagoras theorem,

$\text {Base}^{2}+\text {Height}^{2}=\text {Hypotenuse}^{2}$

ID^2 + KD^2 = KI^2

7^2 + KD^2 = (11.67)^2

49 + KD^2 = 136.1889

Subtract 49 from both sides.

KD^2=87.1889

Taking square root on both sides, we get

KD = 9.34

Area of the triangle = $\frac{1}{2}\times\text{base}\times\text{height}$

$$=\frac{1}{2}\times{7}\times{9.34}$

= 32.69

The area of ΔIDK is 32.69 square units.

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econsta3

31.12.2022

1. 6(3-8)-10

=6(-5)-10

=-30-10

=-40

2.30(3)+15(10)

=90+150

=240

3. 2(3)(3+32+32)

=6(67)

=402

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