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nelyanariba981p555ve

21.12.2021

Mathematics

To the risk of sounding redundant.

$\bf \qquad \qquad \textit{inverse proportional variation}
\\\\
\textit{\underline{y} varies inversely with \underline{x}}\qquad \qquad y=\cfrac{k}{x}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------$

$\bf (5,4)\textit{ we also know that }
\begin{cases}
x=5\\
y=4
\end{cases}\implies 4=\cfrac{k}{5}\implies 20=k
\\\\\\
therefore\qquad \boxed{y=\cfrac{20}{x}}
\\\\\\
(x,7)\textit{ when y = 7, what is \underline{x}?}\qquad 7=\cfrac{20}{x}\implies x=\cfrac{20}{7}\implies x=2\frac{6}{7}$

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