Mathematics: Can someone me and solve this in a good way it’s really urgent

Can someone me and solve this in a good way it’s

tobywaffle1234

10.03.2022

We know that :

✿ (p - q)² = (p)² - 2(p)(q) + (q)²

The Given Problem is in the Same Form

Where :

✿ $\mathsf{p = (3 + \frac{a}{4})}$

✿ $\mathsf{q = (1 + \frac{a}{4})}$

$\mathsf{\implies (3 + \frac{a}{4})^2 - 2(3 + \frac{a}{4})(1 + \frac{a}{4}) + (1 + \frac{a}{4})^2 = [(3 + \frac{a}{4}) - (1 + \frac{a}{4})]^2}$

$\mathsf{\implies (3 + \frac{a}{4})^2 - 2(3 + \frac{a}{4})(1 + \frac{a}{4}) + (1 + \frac{a}{4})^2 = [(3 + \frac{a}{4} - 1 - \frac{a}{4})]^2}$

$\mathsf{\implies (3 + \frac{a}{4})^2 - 2(3 + \frac{a}{4})(1 + \frac{a}{4}) + (1 + \frac{a}{4})^2 = [(3 - 1)]^2}$

$\mathsf{\implies (3 + \frac{a}{4})^2 - 2(3 + \frac{a}{4})(1 + \frac{a}{4}) + (1 + \frac{a}{4})^2 = [2]^2}$

$\mathsf{\implies (3 + \frac{a}{4})^2 - 2(3 + \frac{a}{4})(1 + \frac{a}{4}) + (1 + \frac{a}{4})^2 = 4}$

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