Can someone me? : ) estimate the size of a crowd standing along a 1/4 mile section of a parade route that is 5 feet deep on both sides of the street. assume that 10 people occupy a square measuring 5 feet by 5 feet. a. 2640 people b. 3960 people c. 5280 people d. 7920 people

The size of a crowd standing along with a 1/4 mile section of a parade route: 5280 people

Comparison is an effort to compare two or more objects in terms of shape or size, or number

Proportional Comparisons are comparisons of two or more numbers where one number increases, the other numbers also increase

Can be formulated

so that if:

x = 2

then

While the reversal value comparison is the comparison of two or more numbers where one number increases, the other number decreases in value

Can be formulated

so that if:

x = 2

then

The size of a crowd who can see the parade can be calculated using the principle of proportional comparison

The question stated that 10 people occupy a square measuring 5 feet by 5 feet

means the area occupied by 10 people = 5 ft x 5 ft = 25 ft²

so the ratio is :

Because there are 1/4 mile section of a parade route and 5 feet deep on both sides of the street, the total area

1 mile = 5280 ft

1/4 mile = 1320 ft

Total area = 1320 ft x 5 ft (deep) x 2 (both sides of the street) = 13200 ft²

Then the comparison of points 1 and 2 can be used to calculate the total number of people who saw the parade

Total people =

Total people = 5280 (C)

Divide 80 in a ratio of 3: 2

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percent of 19.5 is 70.59

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The average weight of the top 5 fish

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Keywords: parade, street, area, crowd, comparison

25% if I did the math correctly.