Can someone me. this is an equation for either an arithmetic or geometric sequence.

A6 = -8
a15= -62

There are (15 - 6) terms in between, therefore 9 terms in between.
-8 to -62 ... there is a difference of 54
54 ÷ 9 = 6
Therefore it gets -6 each term.
a6 = -8, a7= -14, a8 = -20

That's an arithmetic sequence. To find the rule of the sequence, we need to find the first term (a₁) and the difference of the sequence (d)

Make an equation system based on what are given by the question.
an = a₁ + d(n - 1)

a₆ = a₁ + d(6 - 1) = -8
a₆ = a₁ + 5d = -8 (first equation)

a₁₅ = a₁ + d(15 - 1) = -62
a₁₅ = a₁ + 14d = -62 (second equation)

Solve the equation to find the value of a₁ and d
Using elimination method, find the value of d from first equation and second equation
a₁ + 14d = -62
a₁ +  5d =   -8
-   (substract)
        9d = -54
          d = -54/9
          d = -6

Using subtitution method, find the value of a₁. Subtitute d with -6 from the first equation.
a₁ + 5d = -8
a₁ + 5(-6) = -8
a₁ - 30 = -8
a₁ = -8 + 30
a₁ = 22

Determine the rule of the sequence
General rule for arithmetic sequence is
an = a + d(n - 1)

Now input the value of a₁ and d to the general rule, then simpllify.
an = a + d(n - 1)
an = 22 + -6(n - 1)
an = 22 -6n + 6
an = 28 - 6n

The rule of the sequence is 28 - 6n

j/5.68=0.71

j=0.71×5.68=4.0328

4.0328