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punkinrichard1oxon2i
12.10.2019 •
Mathematics
Can someone me with i'm not fully understanding this unit.
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Ответ:
Ответ:
Plane A
Step-by-step explanation:
angle of elevation of plane A=41 °
angle of elevation of plane B=43°
height of planes=18 miles
let Δabc be the right triangle formed by the plane A and Δabd be the right triangle formed by the plane B
the ab=18miles
∠c, angle of elevation of plane A=41 °
then distance bc=?
sinc=ab/bc
sin(41°)=18/bc
bc=18/0.65
bc=27.437 miles
Now
∠d, angle of elevation of plane B=43°
then distance bd=?
sinc=ab/bd
sin(43°)=18/bd
bd=18/0.68199
bd=26.393 miles
As bc>bd
Hence, Plane A was farther away from the airport when it was 18 miles from the ground!