Can someone me with part b question zoom into the picture if it’s unreadable. ( for the ! )

    x + 3y = 2

Step-by-step explanation:The line:   y-3 = 3(x+1)   or   y = 3x+4

You may (1) first find the equation of the perpendicular line that passes thru (5,-1), then convert it to Standard Form or (2) convert the equation to Standard Form, then find the equation of the line that passes thru (5,-1).  See if you can follow both methods:

Important:  If a line has slope m, then all perpendicular lines have a slope of  (-1/m).  That's called the negative reciprocal.

(1) find the equation in slope-intercept form, then convert to Standard Form

   The line:   y-3 = 3(x+1)   or   y = 3x+4

   Perpendicular line:    y = (-1/3)x + b     [and we need point (5,-1) to find b

               -1 = (-1/3)(5) + b

               -1 = -5/3 + b

                 2/3 = b

    The perpendicular line is:    y = (-1/3)x + 2/3

    The Standard Form of the equation of a line looks like:   Ax+By=C

         The perpendicular line is:

              (1/3)x + y = 2/3

               x + 3y = 2       [by convention, coefficient of x is positive; x is first;

                                         get rid of fractions]

(2) Convert to Standard Form, then find the specific equation

  The line:   y-3 = 3(x+1)   or   y = 3x+4

  In Standard Form:      3x - y = 4        [Note: slope is (-A/B) = (-3)/(-1) = 3

  Slope of all parallel lines:  (-1/3)   [that is, -A/B]

  Equation of parallel line:   x + 3y = D     [and we need point (5,-1) to determine D]

       5 + 3(-1) = D

          2 = D

  The parallel line, in Standard Form, is :     x + 3y = 2