CAN SOMEONE PLZ HELP, I NEED THIS TO MOVE ON!!

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plewse

16.03.2021

Mathematics

$(a+b)^n=\displaystyle\sum_{k=0}^n\binom nka^{n-k}b^k$

where $\dbinom nk=\dfrac{n!}{k!(n-k)!}$ . The second term of the expansion occurs when k=1

.

So the second term of the expansion of $(2r-3s)^{12}$ is

$\dbinom{12}1(2r)^{12-1}(-3s)^1=12(2r)^{11}(-3s)=-73728r^{11}s$

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