Can someone solve and show work possibly?

Number of adult tickets sold = 17

Number of student tickets sold =32

Number of senior citizen tickets sold = 51

Given that a certain school sells:

adult tickets = $ 8 ; student tickets = $ 5 and senior citizen tickets = $ 6

Let the number of adult tickets sold be "a"

Let the number of student tickets sold be "b"

Let the number of senior citizen tickets sold be "c"

For one game 100 tickets were sold for $ 600

Number of adult tickets sold + number of student tickets sold + number of senior citizen tickets sold = 100

a + b + c = 100 eqn 1

Number of adult tickets sold  x price of one adult ticket +  number of student tickets sold x  price of one student tickets +  number of senior citizen tickets sold x price of one senior citizen tickets = 600

8a + 5b + 6c = 600   eqn 2

There are 3 times as many adult tickets sold as senior citizen tickets

Hence we get,

3a = c   eqn 3

Put eqn 3 in eqn 1 we get,

a + b + 3a = 100

4a + b = 100

b = 100 - 4a   eqn 4

Substitute eqn 3 and eqn 4 in eqn 2, we get

8a + 5(100 - 4a) + 6(3a) = 600

8a + 500 - 20a + 18a = 600

6a = 600 - 500

a = 16.67 that is approximately 17

a = 17

Substitute a = 17 in eqn 3,

3(17) = c

c = 51

Substitute a = 17 in eqn 4,

b = 100 - 4(17) = 100 - 68 = 32

b = 32

Thus we get:

number of adult tickets sold = a = 17

number of student tickets sold = b = 32

number of senior citizen tickets sold = c = 51

width = 16 inch.

Step-by-step explanation:

Given,

let the width be x

so, length = 2 in. more than twice its width = 2 + 2x

perimeter = 2l + 2b

we know,

perimeter = 100 in

so, 2l + 2b = 100

after inserting the values we got,

→ 2(2+2x) + 2(x) = 100

→ 4 + 4x + 2x = 100

→ 4 + 6x = 100

→ 6x = 100 - 4 = 96

→ x = 96/6 = 16

therefore, width is x so width of rectangle is 16 inch.

hope this answer helps you dear and may u have a great day ahead.