Mathematics: Can you me with #20? in details i am so lost

Can you me with #20? in details i am so lost

Ответ:

xonyemaa12

05.01.2022

Area of an equilateral triangle is $\frac{ s^{2} \sqrt{3} }{4}$ , where s is length of a side; we have s = 2 + 4 + 2 = 8 mm; then area is $16 \sqrt{3} ;$ ;
Area of a semi-circle = (1/2)π $r^{2}$ , where r is the radius of circle; r = 4/2 = 2 mm; then area is 2π;
The shaded area is $16 \sqrt{3} - 2π = 2( [tex]8 \sqrt{3}$ - π );

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Ответ:

SL10355

22.03.2022

Mathematics

answer ;5

Step-by-step explanation:

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Can you me with #20? in details i am so lost

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