Mathematics: Can you me with 8b and 8c and explain it

Can you me with 8b and 8c and explain it - id881755764, Hannahmiller3773

3ds

30.12.2021

8b) 2x+ $\sqrt{3}$ x

8c) $\frac{x-3\sqrt{x} +2 }{x-4}$

Step-by-step explanation:

8b)

Multiply the top and bottom by 2+ $\sqrt{3}$ to rationalize this fraction

$\frac{x}{2-\sqrt{3} } * \frac{2+\sqrt{3} }{2+\sqrt{3} }$

Simplify the product

$\frac{x(2+\sqrt{3}) }{1}$

Distribute x through the parenthesis

2x+ $\sqrt{3}$ x

8c)

Multiply the top and bottom by $\sqrt{x}-2$ to rationalize this fraction

$\frac{(\sqrt{x}-1)*(\sqrt{x}-2) }{(\sqrt{x}+2)*(\sqrt{x}-2) }$

Simplify the product

$\frac{x-2\sqrt{x}-\sqrt{x}+2 }{x-4}$

Collect like terms

$\frac{x-3\sqrt{x} +2 }{x-4}$

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rachylt8152

10.10.2022

y + 3 = 2(x + 3)

[point-slope; y – y₁ = m(x – x₁)]

y = 2x + 3 [slope-intercept; y = mx + b]

2x – y = -3 [standard form; ax + by = c]

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