Carla volunteered to make pizza for a bake sale, she bought two pounds of cheese and six pounds of dough. She spent $20.00 at the store for her ingredients. After making the pizzas she thought they looked good and would make more. She went back to the store and bought one more pound of cheese and five more pounds of dough and spent a total of $15.00. How much did each pound of cheese cost and how much did each pound of dough cost?

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kayla232734

05.08.2020

Mathematics

1. We need to perform a division by multiplying the dividend with the reciprocal of the divisor. We can apply this rule:

$(\frac{A}{B})/(\frac{C}{D} )=(\frac{A}{B}) (\frac{C}{D})$

In the problem... 2(x^4 +9)/x(x^2 +1)

A =

B = 1C =

D = 1

2(x^4 +9)/x(x^2 +1) changes to $(2(x^4+9))(\frac{1}{x(x^2+1)}$

2. We need to get rid of all the parenthesis in this term. $(2(x^4+9))(\frac{1}{x(x^2+1)}$

All negative factors will change the sign.In the problem $(2(x^4+9))(\frac{1}{x(x^2+1)}$ there isn't any negative factors. So the sign will not change.

$(2(x^4+9))(\frac{1}{x(x^2+1)}$ is now $2(x^4+9)(\frac{1}{x(x^2+1)}$

3. Lastly, we need to perform a multiplication.

We can use this rule: $\frac{A}{B} C=\frac{AC}{B}$ In the problem $2(x^4+9)(\frac{1}{x(x^2+1)}$ the new factors on the numerator are: 2, (x^4+9), 1

Notice that all non-fraction factors are placed in the numerator.The new factors in the denominator are: x, (x^2+1),

Therefore, the answer is: $\frac{2(x^4+9)}{x(x^2+1)}$

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