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sryun
27.03.2021 •
Mathematics
Carlton and Leon are expert bowlers. Seventy percent of Carlton's rolls are strikes, while 67% of Leon's rolls are strikes. Suppose that Carlton and Leon each bowl 25 games. What is the probability that Leon's proportion of strikes is greater than Carlton's for these games?
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Ответ:
The probability that Leon strikes is greater than Carlton strike is 0.40905
Step-by-step explanation:
From the question, we have;
The percentage of Carlton's rolls are strikes,
= 70%
The number of games Carlton played, n₁ = 25
The percentage of Leon's rolls that are strikes,
= 67%
The number of games Leon played, n₂ = 25
Therefore, we have;
Where;
k₁ = 0.7 × 25 = 17.5
k₂ = 0.67 × 25 = 16.75
The test statistic is given as follows;
From the z-table, we have;
The p-value for Carlton strikes is greater than Leon's strike = 0.59095
∴ The p-value for Leon strikes is greater than Carlton strike = 1 - 0.59095 = 0.40905
The probability that Leon strikes is greater than Carlton strike = 0.40905
Ответ:
142506
Step-by-step explanation:
To select a committee we don't require any order , so we use a combination.
The number of combinations of selecting r things out of n things:
So, the number of combinations of selecting 5 members out of 30 =![\dfrac{30!}{5!(30-5)!}=\dfrac{30\times29\times28\times27\times26\times25!}{120\times5!}=142506](/tpl/images/0840/4339/f3a15.png)
Hence, total number of ways= 142506